# 1295 - Find Numbers with Even Number of Digits

[1295 - Find Numbers with Even Number of Digits](https://leetcode.com/problems/find-numbers-with-even-number-of-digits/)

Given an array nums of integers, return how many of them contain an even number of digits.

## Examples

Input: nums = \[12,345,2,6,7896] Output: 2 Explanation: 12 contains 2 digits (even number of digits). 345 contains 3 digits (odd number of digits). 2 contains 1 digit (odd number of digits). 6 contains 1 digit (odd number of digits). 7896 contains 4 digits (even number of digits). Therefore only 12 and 7896 contain an even number of digits.

Input: nums = \[555,901,482,1771] Output: 1 Explanation: Only 1771 contains an even number of digits.

## Constraints

* 1 <= nums.length <= 500
* 1 <= nums\[i] <= 105

## Java Solution

```java
class Solution {
    public int findNumbers(int[] nums) {
        int result = 0;
        for(int i = 0; i < nums.length; i++) {
            if(hasEvenDigits(nums[i])) result++;
        }
        
        return result;
    }
    
    private boolean hasEvenDigits(int num) {
        return String.valueOf(num).length() % 2 == 0;
    }
}
```
