Merge two sorted linked lists and return it as a sorted list. The list should be made by splicing together the nodes of the first two lists.
The number of nodes in both lists is in the range [0, 50]. -100 <= Node.val <= 100 Both l1 and l2 are sorted in non-decreasing order.
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if(l1 == null)return l2;
if(l2 == null)return l1;
ListNode head = new ListNode(0);
ListNode pointer = head;
while(l1 != null && l2 != null) {
if(l1.val < l2.val) {
pointer.next = l1;
l1 = l1.next;
} else {
pointer.next = l2;
l2 = l2.next;
}
pointer = pointer.next;
}
if(l1 != null) {
pointer.next = l1;
}
if(l2 != null) {
pointer.next = l2;
}
return head.next;
}
}